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Note of Quantity by Saqib Imran

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Quantity Notes By Engineer Saqib Imran 1 cm = 0.3937 inch 1 Decigram = 10 Centigram 1 Decagram = 10 Gram 1000 Sq.m = 1 He acre 1 Hectogram = 10 Decigram 100 kg = 1 Cointal 1 kg = 10 Hectogram 10 Cointol = 1 Ton 1 kg = 2.204 Pounds 10 Hectometer = 1 Km 1 pound = 16 Ounce 1 Yard = 0.914 m 1 Ton = 20 Maan 1 m = 1.09 Yard 1 Ton = 1000 kg 1 Meter Square = 10.76 Sft 10 cm = 1 decimeter 1 meter cube = 35.32 Cft 1 Maan = 50 kg 1 Marla = 9 Sarsai 10 decimeter = 1 m 1 Sarsai = 30.25 Sft 10 m = 1 Decameter 1 Canal = 5445 Sft 10 Decameter = 1 Hectometer 1 Pound = 0.453 kg 10 mm = 1 cm 1 kg = 9.81 Newton 10 Milliliter = 1 Centiliter 1 Kilo newton = 1000 Newton 10 Centiliter = 1 Decalitre 1 Liter = 0.93 kg 10 Deciliter = 1 Liter 1 Kips = 0.93 kg 10 liter = 1 Decaliter 10 Decaliter = 1 Hectoleter 10 Hectoliter = 1 Kiloliter 100 Square meter = 1 Acre Cell No : 0341-7549889

Text from page-3

Quantity Notes By Engineer Saqib Imran RATE ANALYSIS I. II. III. IV. V. VI. VII. VIII. IX. X. XI. XII. No of bricks in 1 Cft = 13.5 or 14.2 No of bricks in 1 cum = 500 bricks Volume of 1 brick in Foot system = 0.0703 Cft Volume of one brick in meter system = 0.002 Cum Dry mortar used in masonary work = 30 % Wet mortar convert to dry mortar then multiplying with 1.27 Wet concrete convert to dry multiply with 1.54 Volume of 1 cement bag = 1.25 Cft Volume of one cement bag = 0.035 Cum Weight of steel in 1 Cft = 490 Lbs Weight of steel in 1 Cum = 7850 kg Volume of block = 0.3075 Cell No : 0341-7549889

Text from page-4

Quantity Notes By Engineer Saqib Imran To Find Quantity In A Foot System Q No 1: Determine The Quantities Of Various Materials Used In 1804 Cft Brick Works In Cement Mortar Ratio 1:4. Solution: Quantity Of Bricks = 1805 Cft Find Bricks Cement And Sand 1: Bricks Quantity Of Bricks = 1805 Cft Volume Of One Brick = 0.0703 Cft No Of Bricks In 1805 Cft = 1805/0.0703 =25675 Bricks 2: Cement Dry Mortar Used In Masonary = 30 % Quantity Of Mortar = 1805 x 30/100 = 541.5 Cft Sum Of Ratio = 1 + 4 = 5 Cement = 1/5 X 541.5 = 108.3 Cft Convert It To Bags One Bag Volume = 1.25 Cft No Of Bags In 108.3 Cft = 108.3/1.25 = 86.64 Or 87 Bags 3: Sand 4/5 x 541.5 = 433.2 Cft Abstract Of Cost Bricks brick 1 trip = 12’000 Rs In one dumper 2000 bricks 2000/2000 = 12000/2000 = 6 Rs 1 brick = 6 Rs No of bricks= 25675 x 6 = 2’14’050 Rs Cement Cement 1 trip = 80’000 Price of 1 bag = 400 400/400 = 80’000/400 = 200 1 Cft = 200 Rs Cell No : 0341-7549889

Text from page-5

Quantity Notes By Engineer Saqib Imran No of Cement Bags = 87 87 x 200 = 17400 Rs Qs: Determine the Quantities of various material to prepare 10 Cum concrete Ratio 1:2:4. Sol: Quantity of Material = 10 Cum Quantity of Dry Material = 10 x 1.54 = 15.4 Ratio of concrete = 1:2:4 Sum of ratio: 1 + 2 + 4 = 7 Cement: 1/7 x 15.4 = 2.2 Cum One bag = 0.035 cum 2.2/0.035 = 62.86 Bags Sand: 2/7 x 15.4 = 4.4 Cum Bajri: 4/7 x 15.4 = 8.8 Cum  ________________________$_______________________________________* D.P.C Qs: Quantity of D.p.c = 97 sqm thichkness of d.p.c = 2.5 cm Ratio: 1:2:4 Find The Quantity Of Various Materials. Sol: Qty of D.p.c = 97 sqm Change it to volume Thickness of D.p.c + 2.5 cm Change it to meter 2.5/100 = 0.025 Cum Volume = 97 x 0.025 2.42 Cum Convert It to Dry = 2.42 x 1.54 = 3.73 cum Mixing Ratio: 1:2:4 Sum of Ratio = 1 + 2 + 4 = 7 Cement: 1/7 x 3.73 = 0.532 Cum 1 bag = 0.035 0.532/0.035 = 15.2 Bags Sand: 2/7 x 3.73 1.06 Cum Bajjri: 4/7 x 3.73 = 2.13 Cum Cell No : 0341-7549889

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