×
If you belive yourself, anything is possible.
--Your friends at LectureNotes
Close

Note for Mechanics - MECH By MD WESH KARNI

  • Mechanics - MECH
  • Note
  • 161 Views
  • Uploaded 1 year ago
0 User(s)
Download PDFOrder Printed Copy

Share it with your friends

Leave your Comments

Text from page-1

Engineering Mechanics - Statics Chapter 1 Problem 1-1 Represent each of the following combinations of units in the correct SI form using an appropriate prefix: (a) m/ms (b) μkm (c) ks/mg (d) km⋅ μN Units Used: μN = 10 −6 μkm = 10 N −6 km 9 Gs = 10 s 3 ks = 10 s mN = 10 −3 −3 ms = 10 N s Solution: ( a) m 3m = 1 × 10 ms s m km =1 ms s ( b) μkm = 1 × 10 −3 m μkm = 1 mm ( c) ks 9 s = 1 × 10 mg kg ks Gs =1 mg kg ( d) −3 km⋅ μN = 1 × 10 mN km⋅ μN = 1 mm⋅ N 1 © 2007 R. C. Hibbeler. Published by Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This material is protected under all copyright laws as they currently exist. No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher.

Text from page-2

Engineering Mechanics - Statics Chapter 1 Problem 1-2 Wood has a density d. What is its density expressed in SI units? Units Used: Mg = 1000 kg Given: d = 4.70 slug ft 3 Solution: 1slug = 14.594 kg d = 2.42 Mg m 3 Problem 1-3 Represent each of the following combinations of units in the correct SI form using an appropriate prefix: (a) Mg/mm (b) mN/μs (c) μm⋅ Mg Solution: 3 ( a) 6 Mg 10 kg 10 kg Gg = = = −3 mm m m 10 m Mg Gg = mm m ( b) mN μs mN μs ( c) = 10 −3 10 = N −6 3 = s 10 N kN = s s kN s ( −6 μm⋅ Mg = 10 )( 3 ) m 10 kg = 10 −3 m⋅ kg μm⋅ Mg = mm⋅ kg 2 © 2007 R. C. Hibbeler. Published by Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This material is protected under all copyright laws as they currently exist. No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher.

Text from page-3

Engineering Mechanics - Statics Chapter 1 Problem 1-4 Represent each of the following combinations of units in the correct SI form: (a) Mg/ms, (b) N/mm, (c) mN/( kg⋅ μs). Solution: 3 ( a) 6 Mg 10 kg 10 kg Gg = = = −3 ms s s 10 s Mg Gg = ms s N = mm ( b) 1N 10 −3 = 10 3N m m = kN m N kN = mm m mN ( c) kg⋅ μs 10 = mN kg⋅ μs −3 −6 10 = N = kg⋅ s kN kg⋅ s kN kg⋅ s Problem 1-5 Represent each of the following with SI units having an appropriate prefix: (a) S1, (b) S2, (c) S3. Units Used: kg = 1000 g −3 ms = 10 s 3 kN = 10 N Given: S1 = 8653 ms S2 = 8368 N S3 = 0.893 kg Solution: ( a) S1 = 8.653 s 3 © 2007 R. C. Hibbeler. Published by Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This material is protected under all copyright laws as they currently exist. No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher.

Text from page-4

Engineering Mechanics - Statics ( b) S2 = 8.368 kN ( c) S3 = 893 g Chapter 1 Problem 1-6 Represent each of the following to three significant figures and express each answer in SI units using an appropriate prefix: (a) x, (b) y, and (c) z. Units Used: 6 MN = 10 N μg = 1 × 10 −6 gm 3 kN = 10 N Given: x = 45320 kN ( y = 568 × 10 5 ) mm z = 0.00563 mg Solution: ( a) x = 45.3 MN ( b) y = 56.8 km ( c) z = 5.63 μg Problem 1-7 Evaluate ( a⋅ b)/c to three significant figures and express the answer in SI units using an appropriate prefix. Units Used: μm = 10 −6 m Given: a = ( 204 mm) 4 © 2007 R. C. Hibbeler. Published by Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This material is protected under all copyright laws as they currently exist. No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher.

Lecture Notes