×
REMEMBER THAT THE REASON YOU ARE DOING THIS IS TO MAKE YOUR LIFE BETTER
--Your friends at LectureNotes
Close

Note for Pipes and Cistern - PC by Placement Factory

  • Pipes and Cistern - PC
  • Note
  • Quantitative Aptitude
  • Placement Preparation
  • 1931 Views
  • 61 Offline Downloads
  • Uploaded 1 year ago
0 User(s)
Download PDFOrder Printed Copy

Share it with your friends

Leave your Comments

Text from page-2

A  60 B  75 L.C.M.  300 In 1 min, A fills 300  5l 60 B fills 300  4l 75 Hence in 50 min, A and B can fill Capacity of tank- 300 tank filled in 1 min= 5+4=9 l  9  50  450l l l 150 of tank was emptied by pipe c in 50 minutes. Hence in 1 minutes, Pipe C will empty So to empty full tank of 300 150  3l 50 l 300 3 It will take = 100 minutes Q.3 Two, taps A and B can fill a tank in 10 hours and 8 hours respectively . If both the taps are opened simultaneously them how many hours before tap B should be closed so that the tank fills in 5 hours.? SolutionA  10 B8 L.C.M  40 Hence in 1 hour, A will fill A remains open fill end. So A fills  5  4  20l 40  4l 10 and B will fill 40  5l 8 of the tank. ( in 5 hours) l Hence remaining 20 must be filled by B. l 20  4hours 5 So to fill 20 , B takes Q.4 Pipe A and B fill a cistern in 9 hours and 18 hours respectively but a third pipe C can empty the tank in 27 hours. If all the pipes are opened Pipes and cisterns Page 2

Text from page-3

simultaneously but after 4 hours pipe C is closed, then calculate the time in which the tank will be filled? SolutionA9 B  18 C  27 L.C.M  54 l l l In 1 hour, A fill 6 , B fill 3 and C empties 2 . C is open only for 4 hours. Tank filled in 4 house = (6  3  2)  4  28l Tank to be filled after 4 hours =54-28=26 l 26 26  hours 63 9 l 26 will be filled by A and B in 5 Pipe A and B can fill a cistern in 12 minutes and 15 minutes respectively but a third pipe C can empty it in 6 minutes. The first two pipes are kept open for 5 minutes and then pipe C is also opened. Find the time taken to empty the cistern. SolA  12 B  15 C  6 L.C.M  60 l l l In 1 hour, A fills 5 , B fills 4 and empties 10 , A and b are open for initial 5 l minutes, which fill (5+4) =45 of tank. Now C is also open. So in 1 minute = 5+4-10=-1 L of tank is emptied. l So empty 45 , it will take 45 minutes. Pipes and cisterns Page 3

Text from page-4

2 th 5 Q.6 A cistern is filled. A pipe A can fill it in 10 minutes and Pipe b can empty it in 6 minutes. If both pipes are opened simultaneously. How long will they take to empty the cistern. SolA  10 B  6 L.C.M  30 l l In 1 minute, A fills 3 . and B empties 5 of tank. But tank is 2 5 filled 2   30  12l 5 When both A and B are opened= 3-5=2 l l 2 of tank is emptied in 1 minutes. 12  2 l 12 of tank is emptied in 6 minutes 7. Pipe A and B can fill a cistern in 10 hours and 15 hours respectively. Both the pipes are open together to fill the tank, but when the tank is develop in the tank which empties by Pipe A and B to fill the cistern. Solution- 1 th 12 l l l Both are open so in 1 hour (3+2)=5 of tank is filled. Pipes and cisterns filled, a tank of water of the tank. Find the time taken A  10 B  15 L.C.M.  30 In 1 hour, A fills 3 and B fills 2  th 6 Page 4

Text from page-5

5l  1 th 6 Part of tank. Remaining tank to be filled = 30-5=2 Now 11 th 12 1 th 12 l of tank in emptied by leak. Of the tank is only filled by A and B 5 So in 1 hour = 11 55  l 12 12 of tank is filled.  l So to filled 25 , they take 25 60  hours 55 11 12 1 Total time taken to fill the tank= Pipes and cisterns 60 71  hours 11 11 Page 5

Lecture Notes